What is the distance between the following polar coordinates?: $(8, \frac{- 23 π}{12}), (5, \frac{- 3 π}{8})$ $(8,(-23pi)/12), (5,(-3pi)/8)$

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What is the distance between the following polar coordinates?: $(8, \frac{- 23 π}{12}), (5, \frac{- 3 π}{8})$ $(8,(-23pi)/12), (5,(-3pi)/8)$

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Answer 1 · 2018-02-13T08:37:14

$d = = 8.863$ $d==8.863$

Explanation:

The rectangular coordinates of the first point are:
$x = 8 cos (\frac{- 23 π}{12}); y = 8 sin (\frac{- 23 π}{12})$ $x=8cos((-23pi)/12); y=8sin((-23pi)/12)$
$x = 7.727, y = 2.071$ $x=7.727, y=2.071$
The rectangular coordinates of the first point are:
$x = 5 cos (\frac{- 3 π}{8}); y = 5 sin (\frac{- 3 π}{8})$ $x=5cos((-3pi)/8); y=5sin((-3pi)/8)$
$x = 1.913, y = - 4.619$ $x=1.913, y=-4.619$
Distance between the coordinates is given by:
$d = \sqrt{{(1.913 - 7.727)}^{2} + {(- 4.619 - 2.071)}^{2}} = 8.863$ $d=sqrt((1.913-7.727)^2+(-4.619-2.071)^2)=8.863$

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What is the distance between the following polar coordinates?: $(8, \frac{- 23 π}{12}), (5, \frac{- 3 π}{8})$ $(8,(-23pi)/12), (5,(-3pi)/8)$

1 Answer

Explanation:

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What is the distance between the following polar coordinates?: (8,(-23pi)/12), (5,(-3pi)/8) (8,−23π12),(5,−3π8) (8,(-23pi)/12), (5,(-3pi)/8)

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Explanation:

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What is the distance between the following polar coordinates?: $(8, \frac{- 23 π}{12}), (5, \frac{- 3 π}{8})$ $(8,(-23pi)/12), (5,(-3pi)/8)$