How do you find the foci and sketch the hyperbola $x^2-y^2=1$ ?

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Answer 1 · 2018-02-10T13:02:08

$(+-1,0)$ would be the foci

graph{x^2-y^2=1 [-10, 10, -5, 5]}

given equation of hyperbola, $x^2−y^2=1$

the general equation for hyperbolas with center at origin and foci on x axis is $x^2/a^2−y^2/b^2=1$ , where the foci are $(+-a'0)$

therefore, the foci for, $x^2−y^2=1$ is, $(+-1,0)$

How do you find the foci and sketch the hyperbola x^2-y^2=1x^2-y^2=1?