How do you find the center and vertex for #-x^2 + y^2 – 2x – 2y – 9 = 0#?
1 Answer
Jun 23, 2015
Centre (-1,1), vertices (-1,4) and (-1, -2)
Explanation:
Write the equation by completing the squares as
Or
This is an vertical hyperbola with centre at (-1,1)
Vertices would therefore be (-1, 1+3) and (-1, 1-3) that is (-1,4) and (-1,-2)
