How do you graph, label the vertex, axis of symmetry and x intercepts of y=5(x-2/5)(x-11/5)?

1 Answer
Widi K.
Feb 8, 2018

(13/10,-81/20)
I hope this help

Explanation:

y=5(x-2/5)(x-11/5)
1.Apply to distributive property
2. Cancel the common factor of 5
3. Simplify
5(x-13/10)^2-81/20
y=5(x-13/10)^2-81/20
x=13/10

Use the Vertex Form is y=a(x-h)^2+k
a=5
h=13/10
k=-81/20

Find the vertex (h,k)
(13/10,-81/20)
Find p with formula 1/4a
1/4*5=1/20
(13/10,-4)
x=-41/10
Table Vertex
X|Y
-1|22.4
0|4.4
2|-1.6
3|10.4

Vertex: (13/10)
Focus:(13/10,-4)
Axis of symmetry: x= 13/10
Directrix: y=-41/10

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