How do you graph the parabola $y= - 1/2 * x^2$ using vertex, intercepts and additional points?

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How do you graph the parabola $y= - 1/2 * x^2$ using vertex, intercepts and additional points?

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Answer 1 · 2018-02-08T05:32:32

I hope this help.

Explanation:

Using Vertex
Y= $-1/2*x^2$

Y= $-x^2/2$

Use the Vertex Form is y= $a(x-h)^2+k$
a= $-1/2$

h= 0
k=0
{(0,0)
Vertex graph{y=-1/2x^2 [-10, 10, -5, 5]}

Intercept
Find P the distance from Vertex to the focus
$-1/2$
Find focus (h,k+p)
(0, $-1/2$ )
x=0

y= $1/2$ (this answer get from subtract p from the y-coordinate k of the vertex if the parabola opens up or down "y=k-p")
Vertex (0,0)
Focus: (0, $-1/2$ )
Axis of Symmetry: x=0
Directrix: y= $1/2$

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How do you graph the parabola $y= - 1/2 * x^2$ using vertex, intercepts and additional points?

1 Answer

Explanation:

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How do you graph the parabola y= - 1/2 * x^2y= - 1/2 * x^2 using vertex, intercepts and additional points?

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Explanation:

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How do you graph the parabola $y= - 1/2 * x^2$ using vertex, intercepts and additional points?