How do you graph the parabola $y = (x-2)^2 +2$ using vertex, intercepts and additional points?

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Answer 1 · 2018-02-07T18:13:37

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$y-2=(x-2)^2$
It is of the form $Y=4AX^2$ [an upward parabola]

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Vertex is (2,2)**

For y intercept put x=0 we get y=6* *

Some points (0,6),(2,2) (4,6)

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Final Graph
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How do you graph the parabola y = (x-2)^2 +2y = (x-2)^2 +2 using vertex, intercepts and additional points?