Is $5 \frac{1}{3} - 3 \frac{9}{18}$ $5 1/3 -3 9/18$ equal to $2 \frac{5}{6}$ $2 5/6$ ?

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Is $5 \frac{1}{3} - 3 \frac{9}{18}$ $5 1/3 -3 9/18$ equal to $2 \frac{5}{6}$ $2 5/6$ ?

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Answer 1 · 2018-01-26T19:31:56

No, assuming I read your question correctly. It was a little confusing.

Explanation:

$5 \frac{1}{3} = \frac{16}{3}$ $5 1/3 = 16/3$

$- 3 \frac{9}{18} = - \frac{7}{2}$ $-3 9/18 = -7/2$

so

$\frac{16}{3} - \frac{7}{2} = \frac{(16 \times 2) - (7 \times 3)}{3 \times 2} = \frac{32 - 21}{6} = \frac{11}{6}$ $16/3 - 7/2 = ((16xx2) - (7xx3))/(3xx2) = (32-21)/6 = 11/6$

$\frac{11}{6}$ $11/6$ as a mixed number form is $1 \frac{5}{6}$ $1 5/6$ .

Answer 2 · 2018-02-16T14:14:17

Th answer is $1 \frac{5}{6}$ $1 5/6$ and not $2 \frac{5}{6}$ $2 5/6$

Explanation:

$5 \frac{1}{3} - 3 \frac{9}{18} \leftarrow$ $5 1/3-3 9/18" "larr$ can be simplified

$5 \frac{1}{3} - 2 \frac{1}{2}$ $5 1/3 -2 1/2$

$= 2 \frac{? - ?}{6} \leftarrow$ $=2 (?-?)/6" "larr$ subtract the whole numbers and find LCD

$= 2 \frac{2 - 3}{6} \leftarrow$ $= 2 (2-3)/6" "larr$ find equivalent fractions

$= 2 \frac{- 1}{6}$ $= 2 (-1)/6$

$= 1 \frac{5}{6}$ $= 1 5/6$

Therefore the answer $2 \frac{5}{6}$ $2 5/6$ is not correct.

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~another method
$= 2 \frac{2 - 3}{6}$ $= 2 (2-3)/6$

$= 1 \frac{6 + 2 - 3}{6} \leftarrow 1 = \frac{6}{6}$ $= 1 (6+2-3)/6" "larr1 = 6/6$

$= 1 \frac{5}{6}$ $= 1 5/6$

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2 Answers

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