How do you solve $\frac { 4} { 5} x + \frac { 7} { 2} = \frac { 3} { 10}$ ?

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Answer 1 · 2018-01-21T06:49:06

See below

$4/5 x + 7/2 = 3/10$

First take LCM on both the sides

$-> (8x + 35 = 3)/10$

Now you can eliminate the LCM

$-> 8x + 35 = 3$

$-> 8x = 3 - 35$

$-> 8x = -32$

Divide both sides by 8

$-> cancel8^1*x/(cancel8) = cancel(-32)^-4/(cancel8)$

$-> x = -4$

Answer 2 · 2018-01-21T06:49:35

take LCM and solve

taking LCM in
$4/5x + 7/2 = 3/10$

$=> 8/10x + 35/10 = 3/10$

$=> 8x + 35 = 3$

$=> 8x =-32$

$=> x=-4$
hope u find it helpful :)

How do you solve \frac { 4} { 5} x + \frac { 7} { 2} = \frac { 3} { 10}\frac { 4} { 5} x + \frac { 7} { 2} = \frac { 3} { 10}?