How do you solve #16- 2c = - 20- 20c#?

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Answer 1 · 2018-01-20T03:22:48

#c = -2#

Begin with the equation

#16 - 2c = -20 -20c#

Use the additive inverse to move the terms with the variables to the same side

#16 - 2c + 20c = -20 cancel(-20c) cancel (+20c)#

#16 + 18c = -20#

Use the additive inverse to move the constant terms to the same side

#cancel16 + 18c cancel(-16)= -20 -16#

#18c = -36#

Use the multiplicative inverse to isolate the variable

#(cancel(18)c)/cancel(18) = (-36)/18#

Solution #c = -2#.