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How do you differentiate #x^-7 - 7x^-1#?

1 Answer

Jan 16, 2018

#-7x^-8+7x^-2#

Explanation:

Let #y=x^-7-7x^-1#

#y'=(x^-7)'-(7x^-1)'#

By the power rule #(x^n)'=nx^(n-1)# we get:

#y'=-7x^(-7-1)-7times(-1x^(-1-1))#

By simplifying, we get:

#-7x^-8+7x^-2#

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