How do you solve #6- 2y = - 4y + 8#? Algebra Linear Equations Two-Step Equations and Properties of Equality 1 Answer Heyopeeps · Stefan V. Jan 15, 2018 #y=1# Explanation: Do #6-2y +2y=-4y+8 +2y# #6= -2y+8# Then #6 -8= -2y+8 -8# #-2=-2y# Divide both sides by #-2# and you get #y=1# Answer link Related questions How do you solve two step equations? How do you check solutions to two step equations? What is an example of a two step equation with no solution? How do I check to see if the solution is 1 for the equation #2x+1=3#? Is there more than one way to solve a 2 step equation? How do you solve #-m+3=3#? How do you solve #-5y-9=74#? How do you solve #5q - 7 = \frac{2}{3}#? How do you solve #0.1y + 11 =0#? How do you solve #\frac{5q-7}{12} = \frac{2}{3}#? See all questions in Two-Step Equations and Properties of Equality Impact of this question 1419 views around the world You can reuse this answer Creative Commons License