Question #f2e0e

2 Answers
Alan P.
Jan 3, 2018

Photo of question is incomplete.
No solution is possible.

Parabola
Jan 3, 2018

Not enough information to pinpoint the exact values of the variables.

Explanation:

First, let's simplify the second equation.
We have, (ax)/b-(by)/a=(a^4-b^4)/(ab)
We use the common denominator ab to get:
(ax xxa)/(ab)-(b xxby)/(ab)=(a^4-b^4)/(ab)
(a^2x)/(ab)-(b^2y)/(ab)=(a^4-b^4)/(ab)
ab[(a^2x)/(ab)-(b^2y)/(ab)=(a^4-b^4)/(ab)]
a^2x-b^2y=a^4-b^4
We can quite safely say that a^2x=a^4 and b^2y=b^4
When we simplify this, we get: x=a^2 and y=b^2

And we see that both of the equations hold true when we plug these values into them when a!=0 and b!=0. As long as the values you use fit these requirements, the equations will always hold true. Without enough information, there is infinitely many solutions you could have.

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