If $8 L$ $8 L$ of a gas at room temperature exerts a pressure of $32 k P a$ $32 kPa$ on its container, what pressure will the gas exert if it the container's volume changes to $4 L$ $4 L$ ?

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Answer 1 · 2017-12-28T09:55:49

$32 k P a$ $32kPa$

As, here the temperature is constant
Hence,according to the ideal gass law:

$P_{1} V_{1} = P_{2} V_{2}$ $P_1V_1=P_2V_2$

$or, 8 L \times 32 k P a = 4 L \times P_{2}$ $or,8Lxx32kPa=4LxxP_2$

$or, P_{2} = \frac{8 L \times 32 k P a}{4 L}$ $or,P_2=(8Lxx32kPa)/(4L)$

$:.P_2=64kPacolor(brown)$

So,we have to exert (64-32) kPa or 32 kPa pressure.

If 8 L8L8 L of a gas at room temperature exerts a pressure of 32 kPa32kPa32 kPa on its container, what pressure will the gas exert if it the container's volume changes to 4 L4L4 L?