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How do you find the vertex of #y= -x^2+ 4x + 2#?

1 Answer

Dec 27, 2017

#-(x-2)^2+6#

Explanation:

#−x^2+4x+2#

#=>-1*[x^2-4x-2]#

#=>-1*[(x^2-2*2x+2^2)-2^2-2]#

#=>-1*[(x-2)^2-4-2]#

#=>-1*[(x-2)^2-6]#

#(-(x-2)^2+6)/#

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