The hiking trail is $7 \frac{1}{3}$ $7 1/3$ miles long. There are $6$ $6$ markers posted evenly along the trail to direct hikers. How far apart are the markers placed?

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The hiking trail is $7 \frac{1}{3}$ $7 1/3$ miles long. There are $6$ $6$ markers posted evenly along the trail to direct hikers. How far apart are the markers placed?

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Answer 1 · 2017-12-20T01:56:34

$1 \frac{1}{3}$ $1 1/3$ miles apart.

Explanation:

The trail is $7 \frac{1}{3}$ $7 1/3$ miles long, and there are $6$ $6$ markers on the trail.

In order to solve this, you have to divide $7 \frac{1}{3}$ $7 1/3$ by $6$ $6$ . To do this, you must first change $7 \frac{1}{3}$ $7 1/3$ into an improper fraction of $\frac{22}{3}$ $22/3$ . You find this by multiplying the whole number, $7$ $7$ , by the denominator, $3$ $3$ , and then adding the numerator, $1$ $1$ .

After you change the fraction, you take $\frac{22}{3}$ $22/3$ and divide it by $6$ $6$ .

$\frac{22}{3} \div 6$ $22/3 div 6$

To do this, you must first change $6$ $6$ into a fraction. You can change any whole number into a fraction by putting it over $1$ $1$ , in this case, like this: $\frac{6}{1}$ $6/1$ .

When dividing fractions, you must always flip the second number, so the problem would be

$\frac{22}{3} \times \frac{1}{6}$ $22/3xx1/6$ .

This gives you $\frac{22}{18}$ $22/18$ because you simply multiply across the top and across the bottom.

Now, you take it down to simplest form and get $1 \frac{6}{18}$ $1 6/18$ and then to $1 \frac{1}{3}$ $1 1/3$ .

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The hiking trail is $7 \frac{1}{3}$ $7 1/3$ miles long. There are $6$ $6$ markers posted evenly along the trail to direct hikers. How far apart are the markers placed?

1 Answer

Explanation:

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The hiking trail is $7 \frac{1}{3}$ $7 1/3$ miles long. There are $6$ $6$ markers posted evenly along the trail to direct hikers. How far apart are the markers placed?