Question #d351f

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Question #d351f

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Answer 1 · 2017-12-16T06:27:10

$0.075 moles$ $"0.075 moles"$ or $6.75 grams$ $"6.75 grams"$ .

Explanation:

Consider this molarity equation:

$\frac{no. of moles}{volume in Liters} = Molarity$ $"no. of moles"/"volume in Liters" = "Molarity"$

First, convert $mL$ $"mL"$ to $L$ $"L"$ $\to$ $->$ $750mL = 0.75L$ $"750mL = 0.75L"$

Since you are given the volume and the molarity, plug them into the equation and find the number of moles of oxalic acid required:

$\frac{no. of moles}{0.75 L} = 0.1 M \to no. of moles = 0.075 mol$ $"no. of moles"/("0.75 L") = "0.1 M" -> "no. of moles" = "0.075 mol"$

If you want the amount of oxalic required in grams, then you use dimensional analysis to convert from moles to grams:

$(0.075 mol oxalic acid) \cdot (\frac{90 g oxalic acid}{1 mol oxalic acid}) = 6.75 g oxalic acid required$ $("0.075 mol oxalic acid") * ("90 g oxalic acid"/"1 mol oxalic acid") = "6.75 g oxalic acid required"$

I hope that helps!

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Question #d351f

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