How do you find $dy/dx$ given $x=3y^3+2y$ ?

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Answer 1 · 2017-11-29T05:34:36

$9y^2+\frac{1}{2y}$

I’m assuming you’re asking for the derivative of the RHS:

$3y^3+2y \frac{dy}{dx}$

In that case, apply the power rule to each term.

$3y^3\frac{dy}{dx}+2y\frac{dy}{dx}$

$=9y^2+\frac{1}{2y}$

How do you find dy/dxdy/dx given x=3y^3+2yx=3y^3+2y?