How do you graph the parabola #y = x^2 - x - 2# using vertex, intercepts and additional points?
1 Answer
Firstly, the coefficient of the
The minimum point (vertex) will be when the gradient is zero, so differentiating
So now that we have the x and y coordinates of the minimum, we know to draw the minimum at (0.5, -2.25).
When
Factorizing the quadratic gives
Now we have all the information to draw it. It has a minimum at (0.5, -2.25) crosses the y axis at -2, and crosses the x axis at -1 and 2