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If tanh(x) = 4/5, how do you find the values of the other hyperbolic functions at x?

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Shwetank Mauria · NickTheTurtle

Nov 20, 2017

#sinhx=4/3#, #coshx=5/3#, #tanhx=4/5#
#cothx=5/4#, #sechx=3/5#, #cothx=5/4#

Explanation:

As #tanh^2x+sech^2x=1# and #tanhx=4/5#

hence #sechx=sqrt(1-(4/5)^2)=3/5#

and #coshx=1/sechx=5/3#

#cothx=1/tanhx=5/4#

#sinhx=tanhx*coshx=4/5*5/3=4/3#

#cschx=1/sinhx=3/4#

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