How do you solve the equation #tanG=0.125#?

1 Answer
David B.
Nov 13, 2017

#G = arctan(0.125) ~= 0.124# radians

Explanation:

Let's assume that the question is asking us to solve for #G#. We can use the inverse function of #tan#, sometimes called #arctan# or #tan^(-1)#. To use it we need to take the inverse function of both sides of the equation:

#arctan(tan(G)) = arctan(0.125)#

# => G = arctan(0.125) ~= 0.124# radians

This is the primary solution for #G#. There are other values of #G# which will satisfy this equation

#G ~= 0.124 + n*pi# where #n \in ZZ#

Related questions
See all questions in Solving Trigonometric Equations
Impact of this question
2717 views around the world
You can reuse this answer
Creative Commons License