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Answer 1 · 2017-11-10T21:09:01

#4NH_3 + 5O_2 -> 4NO + 6H_2O#

#NH_3 + O_2 -> NO + H_2O#

Left Hand Side
1 x Nitrogen
3 x Hydrogen
2 x Oxygen

Right Hand Side
1 x Nitrogen
2 x Hydrogen
2 x Oxygen

I would approach this by considering multiplications of 3 and 2:
6, 12, 18....

#2NH_3 + O_2 -> 2NO + 3H_2O#

You can balance the hydrogen and nitrogen here, but not oxygen - you would need 2 1/2 #O_2#

#4NH_3 + 5O_2 -> 4NO + 6H_2O#

The equation is now completely balanced:

Left Hand Side
4 x Nitrogen
12 x Hydrogen
10 x Oxygen

Right Hand Side
4 x Nitrogen
12 x Hydrogen
10 x Oxygen