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Answer 1 · 2017-11-07T00:49:57

$33$ $33$ grams.

Given:

$volume = 100 mL = 0.100 L$ $"volume = 100 mL = 0.100 L"$

$concentration = 2.5 mol/L$ $"concentration = 2.5 mol/L"$

The volume and concentration of a substance are related to the number of moles by the equation

$n = c V$ $n = cV$

where $n$ $n$ is the number of moles, $c$ $c$ is the concentration, and $V$ $V$ is the volume of the substance.

The number of moles of a substance is related to its mass by the equation

$m = n M$ $m = nM$

where $m$ $m$ is the mass, $n$ $n$ is the number of moles, and $M$ $M$ is the molar mass of the substance.

Find the number of moles of solution using the first equation:

$n = c V$ $n = cV$

$n = (2.5 \frac{mol}{L}) (0.100 L)$ $n = (2.5 "mol"/"L")("0.100 L")$

$n = 0.25 mol$ $n = "0.25 mol"$

Find the mass using the second equation:

$m = n M$ $m = nM$

$m = (0.25 mol) (132.14 \frac{g}{mol})$ $m = ("0.25 mol")(132.14 "g"/"mol")$

$m = 33 g$ $m = "33 g"$