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Question #4fed9

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Oct 3, 2017

$\sqrt{8}$ $sqrt(8)$ is between $2$ $2$ and $3$ $3$

Explanation:

$8 > 4 = 2^{2} xxx and xxx 8 < 9 = 3^{2}$ $8 > 4 = 2^2color(white)("xxx")andcolor(white)("xxx")8 < 9 = 3^2$

Therefore
$\sqrt{2^{2}} < \sqrt{8} < \sqrt{3^{2}}$ $sqrt(2^2) < sqrt(8) < sqrt(3^2)$
or
$2 < \sqrt{8} < 3$ $2 < sqrt(8) < 3$

Oct 3, 2017

2 and 3

Explanation:

The next square root after 8 is $\sqrt{9}$ $sqrt9$ = 3. The one before root 8 is $\sqrt{4} = 2$ $sqrt4=2$ .

2 and 3 are consecutive

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