Question #872b5

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Question #872b5

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Answer 1 · 2017-10-01T22:52:45

If #cosa=-1/3#, #a# must be between #90# and #180# degrees. In other words, a in #2#nd quadrant in unit circle. In this quadrant #sina>0#. So, if #cosa=-1/3#, #sina=(2sqrt(2))/3#

After using #sin2a=2sina*cosa# identity, I found #sin2a=-(4sqrt(2))/9#

Explanation:

1) I found #sina# after being given #cosu=-1/3# and #90 < a < 180# conditions.

2) I used #sin2a=2sina*cosa# identity.

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Question #872b5

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