How do you simplify $(c^4d^4f^3)/(c^2d^4f^3)$ ?

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Answer 1 · 2017-09-29T22:49:50

The answer is $c^2$ .

The first thing to take note is that you have several variables (namely, $c$ , $d$ . and $f$ ). Using the exponential law

$(a^n)/(a^m) = a^(n-m)$

we have

$[c^(4-2)][d^(4-4)][f^(3-3)]$

Further applying the law

$a^0 = 1$

the variables $f$ and $d$ are equivalent to $1$ . As such, you are left with

$c^2 * 1 * 1$

which is equal to $c^2$ .

How do you simplify (c^4d^4f^3)/(c^2d^4f^3)(c^4d^4f^3)/(c^2d^4f^3)?