How many moles of $C l$ $Cl$ are in $1.2 \cdot 10^{24}$ $1.2 * 10^24$ formula units of magnesium chloride?

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How many moles of $C l$ $Cl$ are in $1.2 \cdot 10^{24}$ $1.2 * 10^24$ formula units of magnesium chloride?

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Answer 1 · 2017-09-04T16:42:01

$4.0 mol$ $"4.0 mol"$ of ${Cl}^{-}$ $"Cl"^-$ ions.

Explanation:

Magnesium chloride is an ionic compound with an ${Mg}^{2 +}$ $"Mg"^(2+)$ ion and two ${Cl}^{-}$ $"Cl"^-$ ions in each formula unit. Thus:

$1.2 \cdot 10^{24} formula units \cdot \frac{{1 mol MgCl}_{2}}{6.023 \cdot 10^{23} formula units} \cdot \frac{{2 mol Cl}^{-} ions}{{1 mol MgCl}_{2}} = {2.0 mol Cl}^{-} ions$ $1.2*10^24 " formula units" * ("1 mol MgCl"_2)/(6.023*10^23 " formula units")*("2 mol Cl"^(-) " ions")/("1 mol MgCl"_2) = "2.0 mol Cl"^(-) " ions"$

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How many moles of $C l$ $Cl$ are in $1.2 \cdot 10^{24}$ $1.2 * 10^24$ formula units of magnesium chloride?

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How many moles of $C l$ $Cl$ are in $1.2 \cdot 10^{24}$ $1.2 * 10^24$ formula units of magnesium chloride?