Question #b2f8a

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Question #b2f8a

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Answer 1 · 2017-08-18T19:35:44

Original price was $$ 70$ $$70$

Explanation:

You can write an equation and solve it.

Let the original price be $x$ $x$
If a discount of $40 %$ $40%$ is given, it means a price of $60 %$ $60%$ was paid.

$60 % of x = 42$ $60% " of " x =42$

$\frac{60}{100} \times x = 42$ $60/100 xx x = 42$

$x = 42 \times \frac{100}{60}$ $x = 42 xx100/60$

$x = $ 70$ $x = $70$

Or you can write a proportion, comparing the dollars with the percents.

$\frac{x}{42} = \frac{100}{60}$ $x/42 = 100/60$

$x = \frac{42 \times 100}{60}$ $x = (42xx100)/60$

$x = $ 70$ $x = $70$

Answer 2 · 2017-08-18T19:36:24

The sweater originally cost $70.

Explanation:

First, let $x =$ $x=$ the original price of the sweater.
Then, write a statement.
We have a sale which is 40% off. By multiplying the original price by 60%, we effectively subtract 40% from the price.
Therefore: 60% of the original price is $42.
$$ 42 = x \cdot 60 %$ $$42=x*60%$
Substitute .6 for 60%.
$$ 42 = .6 x$ $$42=.6x$
Then divide both sides by .6.
$\frac{$ 42}{.6} = \frac{.6 x}{.6}$ $($42)/.6=(.6x)/.6$
Simplifying, we find:
$x = $ \frac{42}{.6} = $ 70$ $x=$42/.6=$70$
The original price of the sweater before the sale was $70.

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