Can someone please help me with this question,the answer I got was wrong which is this one (4q+3)^2/16. Here is the question? (q+3/4)(q+3/4)

4 Answers
Ratnaker Mehta
Aug 11, 2017

I think the Question demands the Expansion, which is,

(q^2+3/2*q+9/16)=1/16(16q^2+24q+9).

eduarchitect
Aug 11, 2017

see picture

Explanation:

enter image source here

Alan P.
Aug 11, 2017

Your answer looks correct to me, but perhaps the expected form was:
color(white)("XXX")q^2+3/2q+9/16

Explanation:

(q+3/4)(q+3/4)

color(white)("XXX")=q(q+3/4)color(white)("xx")+color(white)("xx")3/4(q+3/4)

color(white)("XXX")=q^2+3/4qcolor(white)("xx")+color(white)("xx")3/4q+9/16

color(white)("XXX")=q^2+6/4q+9/16

color(white)("XXX")=q^2+3/2q+9/16

However, your answer:
(4q+3)^2/16

color(white)("XXX")=(16q^2+24q+9)/16

color(white)("XXX")=(16q^2)/16+(24q)/16+9/16

color(white)("XXX")=q^2+3/2q+9/16

So the results are equivalent.

Jim G.
Aug 11, 2017

"see explanation"

Explanation:

"expand "(q+3/4)(q+3/4)" using FOIL"

=q^2+3/4q+3/4q+(3/4xx3/4)

=q^2+3/2q+9/16

"now express each term as a fraction in "1/16's

"that is "(q^2xx16/16)+(3/4qxx4/4)+9/16

=(16q^2+12q+9)/16

"the numerator is a perfect square "(4q+3)^2

rArr(q+3/4)(q+3/4)=(4q+3)^2/16

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