How do you solve the quadratic using the quadratic formula given $x^2-4x-7=0$ ?

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Answer 1 · 2017-08-09T13:08:28

$x=5.31662479vvx=-1.31662479$

$x^2-4x-7=0$
First you calculate the discriminant.

$D=(-4)^2 -4*1*-7=16+28=44$ ( $D=b^2-4*a*c$ )

Then you use the general formula $x=(-b+-sqrtD)/(2a)$

Which gives: $x= (4+- sqrt44)/(2*1)= x=5.31662479vvx=-1.31662479$

How do you solve the quadratic using the quadratic formula given x^2-4x-7=0x^2-4x-7=0?