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How do you solve the quadratic using the quadratic formula given #x^2-4x-7=0#?

1 Answer

Aug 9, 2017

#x=5.31662479vvx=-1.31662479#

Explanation:

#x^2-4x-7=0#
First you calculate the discriminant.

#D=(-4)^2 -4*1*-7=16+28=44# (#D=b^2-4*a*c#)

Then you use the general formula #x=(-b+-sqrtD)/(2a)#

Which gives: #x= (4+- sqrt44)/(2*1)= x=5.31662479vvx=-1.31662479#

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