What is the derivative of #tan^2(sinx)#?

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What is the derivative of #tan^2(sinx)#?

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Answer 1 · 2017-08-08T22:12:40

#"d"/("d"x) tan^2(sin(x)) = 2tan(sin(x))sec^2(sin(x))cos(x)#

Explanation:

By the chain rule,

#"d"/("d"x) tan^2(sin(x)) = 2*tan(sin(x))* "d"/("d"x) (tan(sin(x)))#,
#"d"/("d"x) tan^2(sin(x)) = 2tan(sin(x))sec^2(sin(x))*"d"/("d"x)(sin(x))#,
#"d"/("d"x) tan^2(sin(x)) = 2tan(sin(x))sec^2(sin(x))cos(x)#.

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What is the derivative of #tan^2(sinx)#?

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