What is the vertex form of $y= (x+6)(x-23)$ ?

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Answer 1 · 2017-07-24T09:48:51

$(x-17/2)^2-825/4$

And the vertex is the point $A(17/2,825/4)$

$y=(x+6)(x-23)=x^2-17x-138=$

$x^2-2*17/2x-138=x^2-2*17/2x+(17/2)^2-(17/2)^2-138=$

$(x-17/2)^2-825/4$

And the vertex is the point $A(17/2,825/4)$

What is the vertex form of y= (x+6)(x-23)y= (x+6)(x-23)?