What is the vertex form of #y= x^2 – 7x – 4#?

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Answer 1 · 2017-07-18T03:17:19

#y = x^2 - 7 x - 4#

use completing a square

#y = (x - 7/2)^2 - (-7/2)^2 - 4#

#y = (x - 7/2)^2 - 49/4 - 16/4#

#y = (x - 7/2)^2 - 65/4#

since # (x - 7/2)^2# is a +ve value, therefore it has a minimum vertex #7/2# at #(7/2, -65/4)#