How do you find the value of the discriminant and state the type of solutions given #-9b^2=-8b+8#?

1 Answer
Ho Kae Boon
Jun 30, 2017

.

Explanation:

If #ax^2+bx+c=0#
Then discriminant#=##b^2-4(a)(c)#
If discriminant#>0#, then solutions are two different real roots
If discriminant #=0#, then solutions are two equal real roots
If discriminant#<0#, then there are no real roots for solutions

In your case,
#-9b^2=-8b+8#
#9b^2-8b+8=0#

Discriminant
#=(-8)^2-4(9)(8)#
#=64-288#
#=-224#

So the type of the solution is ...
There are no real roots.

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