How do you find the value of the discriminant and state the type of solutions given -9b^2=-8b+8?

1 Answer
Jun 30, 2017

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Explanation:

If ax^2+bx+c=0
Then discriminant=b^2-4(a)(c)
If discriminant>0, then solutions are two different real roots
If discriminant =0, then solutions are two equal real roots
If discriminant<0, then there are no real roots for solutions

In your case,
-9b^2=-8b+8
9b^2-8b+8=0

Discriminant
=(-8)^2-4(9)(8)
=64-288
=-224

So the type of the solution is ...
There are no real roots.