How do you multiply #(3x-15)/(4x^2-2x)*(10x-20x^2)/(5-x)#?
1 Answer
15
Explanation:
When multiplying fractions, whether with unknowns in algebra or not, simply multiply the numerators together, and multiply the denominators together, so:
In this case, remembering to keep things in brackets, that would give us:
However this can be simplified by removing common factors of the top and bottom.
We can take out a factor of -3, and write
Also we can take out a factore of -5 and write