How do you factor #8x^3 - 8x^2 - x + 1# by grouping? Algebra Polynomials and Factoring Factoring by Grouping 1 Answer SagarStudy Jun 9, 2017 #8x^3-8x^2-x+1# Take #8x^2# common from first two terms and #-1# from the last two terms. #=8x^2(x-1)-1(x-1)# Take the factor #(x-1)# as common. #=(x-1)(8x^2-1)# Answer link Related questions What is Factoring by Grouping? How do you factor by grouping four-term polynomials and trinomials? Why does factoring polynomials by grouping work? How do you factor #2x+2y+ax+ay#? How do you factor #3x^2+8x+4# by using the grouping method? How do you factor #6x^2-9x+10x-15#? How do you group and factor #4jk-8j^2+5k-10j#? What are the factors of #2m^3+3m^2+4m+6#? How do you factor quadratics by using the grouping method? How do you factor #x^4-2x^3+5x-10#? See all questions in Factoring by Grouping Impact of this question 1828 views around the world You can reuse this answer Creative Commons License