How do you solve and write the following in interval notation: $| 4 − 3x | + 1/2 <-2$ ?

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Answer 1 · 2017-06-06T12:59:44

$O/$

$|4-3x| + 1/2 < -2$
substract on both side by $-1/2$ :
$|4-3x| < -5/2$

This is absurd because $AAx, |x|>=0$
and $-5/2 < 0$

Therefore, the answer is $O/$

How do you solve and write the following in interval notation: | 4 − 3x | + 1/2 <-2| 4 − 3x | + 1/2 <-2?