Question #d16b6

1 Answer

81.44%

Explanation:

Mass of Al(NO_3)_2- 2.5kg
Mass of Mg(NO_3)_2- 2.0kg

-Conversion Factors-

Molar Masses:
Aluminum (Al)- 26.98g/(mol)
Nitrogen(N)- 14.01g/(mol)
Oxygen(O)- 16.00g/(mol)
Magnesium(Mg)- 24.31g/(mol)

Al(NO_3)_2 molar mass
=26.98g/(mol)+2(14.01g/(mol)+3*16.00g/(mol))
=151g/(mol)

Mg(NO_3)_2 molar mass
=24.31g/(mol)+2(14.01g/(mol)+3*16.00g/(mol))
=148.33g/(mol)

Conversion Equation
Al(NO_3)_(2mass)*(Al(NO_3)_(2mols))/(Al(NO_3)_(2mass))*(Mg(NO_3)_(2mols))/(Al(NO_3)_(2mols))*(Mg(NO_3)_(2mass))/(Mg(NO_3)_(2mols))
=2.5kgAl(NO_3)_2*(1molAl(NO_3)_2)/(151gAl(NO_3)_2)*(1molMg(NO_3)_2)/(1molAl(NO_3)_2)*(148.33gMg(NO_3)_2)/(1molMg(NO_3)_2)
=2455.79gMg(NO_3)_2

Percent Yield
"%Yield"=("Actual")/("Theoretical")
=(2000gMg(NO_3)_2)/(2455.79gMg(NO_3)_2)=.8144=81.44%