How do you simplify $\frac{- 2 f^{3} g^{2} h^{0}}{8 f^{2} g^{2}}$ $(-2f^3g^2h^0)/(8f^2g^2)$ ?

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How do you simplify $\frac{- 2 f^{3} g^{2} h^{0}}{8 f^{2} g^{2}}$ $(-2f^3g^2h^0)/(8f^2g^2)$ ?

2 Answers

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Answer 1 · 2017-06-01T05:55:19

ans- -1fh^0/4

Explanation:

-2 (f^3) (g^2) (h^0)/ 8f^2g^2 ----------------(on solving and cancelling in both numerator and denominator f^2, g^2 are common and hence get cancelled)
= -1f(h^0)/4 (thus answer)
...............................hope it helps.....................:)

Answer 2 · 2017-06-01T06:05:20

$\frac{- f}{4}$ $(-f)/4$

Explanation:

$\frac{- 2 f^{3} g^{2} h^{0}}{8 f^{2} g^{2}}$ $(-2f^3g^2h^0)/(8f^2g^2)$

$\frac{- 2}{8} \times f^{3 - 2} g^{2 - 2} \times h^{0}$ $(-2)/8xxf^(3-2)g^(2-2)xxh^0$

$\frac{- 1}{4} \times f \times g^{0} \times h^{0}$ $(-1)/4xxfxxg^0xxh^0$

$\frac{- f}{4}$ $(-f)/4$

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How do you simplify $\frac{- 2 f^{3} g^{2} h^{0}}{8 f^{2} g^{2}}$ $(-2f^3g^2h^0)/(8f^2g^2)$ ?

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Explanation:

Explanation:

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How do you simplify (-2f^3g^2h^0)/(8f^2g^2)−2f3g2h08f2g2(-2f^3g^2h^0)/(8f^2g^2)?

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Explanation:

Explanation:

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How do you simplify $\frac{- 2 f^{3} g^{2} h^{0}}{8 f^{2} g^{2}}$ $(-2f^3g^2h^0)/(8f^2g^2)$ ?