How do you solve for y in $2 y + 8 x = 4$ $2y+8x=4$ ?

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How do you solve for y in $2 y + 8 x = 4$ $2y+8x=4$ ?

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Answer 1 · 2017-05-27T16:51:18

You can't; as the equation involves two variables, it takes another dissimilar equation to provide an intersection point

Explanation:

The most you can do with the equation is expressing $x$ $x$ in terms of $y$ $y$ :
$2 y + 8 x = 4$ $2y+8x=4$
$2 y = - 8 x + 4$ $2y=-8x+4$
$y = - 4 x + 2$ $y=-4x+2$
However, this only provides the Cartesian equation for a line; simply put, as it is a line, there are infinite values for x, which would correspond to infinite values for y that would satisfy the equation.

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How do you solve for y in $2 y + 8 x = 4$ $2y+8x=4$ ?

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