What is the Cartesian form of (-4,(11pi)/4))(4,11π4))?

1 Answer
May 26, 2017

In Cartesian coordinates, (-4,(11pi)/4)(4,11π4) = (2sqrt2, -2sqrt2)(22,22)

Explanation:

If you consider that x=rcosTheta and y=rsinTheta, you can plug in those values from that polar coordinate to find (x,y).

On the unit circle, theta = (11pi)/4 is equal to (3pi)/4.

When you plug it in, x=-4cos((3pi)/4) and y=-4sin((3pi)/4).

More simplified, x=-4*-(sqrt2)/2 and y=-4*(sqrt2)/2.

Once everything is finally simplified, you will get x=2sqrt2 and y = -2sqrt2