What is the Cartesian form of $(- 4, \frac{11 π}{4}))$ $(-4,(11pi)/4))$ ?

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Answer 1 · 2017-05-26T00:17:52

In Cartesian coordinates, $(- 4, \frac{11 π}{4})$ $(-4,(11pi)/4)$ = $(2 \sqrt{2}, - 2 \sqrt{2})$ $(2sqrt2, -2sqrt2)$

If you consider that $x=rcosTheta$ and $y=rsinTheta$ , you can plug in those values from that polar coordinate to find $(x,y)$ .

On the unit circle, $theta = (11pi)/4$ is equal to $(3pi)/4$ .

When you plug it in, $x=-4cos((3pi)/4)$ and $y=-4sin((3pi)/4)$ .

More simplified, $x=-4*-(sqrt2)/2$ and $y=-4*(sqrt2)/2$ .

Once everything is finally simplified, you will get $x=2sqrt2$ and $y = -2sqrt2$

What is the Cartesian form of (-4,(11pi)/4))(−4,11π4))(-4,(11pi)/4))?