How do you evaluate $4( 22- 11) + \frac { 2^ { 4} } { ( 10- 2) }$ ?

Question

1090 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-14T19:28:23

$46$

$4*(22-11)+2^4/(10-2)$

$22-11 = 11$ and $10-2 = 8$

Therefore :

$4*(22-11)+2^4/(10-2)$

$= 4*11+2^4/8" "(and 8=2^3)$

$=> 2^4/8=2^4/2^3 = 2^(4-3)=2^1=2$

You have then

$4*11+2^4/8$

$= 44+2$

$= 46$

How do you evaluate 4( 22- 11) + \frac { 2^ { 4} } { ( 10- 2) }4( 22- 11) + \frac { 2^ { 4} } { ( 10- 2) }?