How do you solve $(y+2)/y=1/(y-5)$ ?

Question

1544 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-14T15:19:09

First, note that $0$ and $-5$ cannot be the answers.

Then, multiply by $y*(y-5)$ :

$(y+2)/y = 1/(y-5) <=> (y-5) (y+2) = y$

$<=> y^2 -4y -10 =0$

And you get a simple quadratic equation.

How do you solve (y+2)/y=1/(y-5)(y+2)/y=1/(y-5)?