How do you balance #H_2SO_4 + B(OH)_3 -> B_2(SO_4)_3 + H_2O#?
1 Answer
Explanation:
We have:
LHS
H= 2 + 3= 5
S= 1
B= 1
O= 4 + 3= 7
RHS
H= 2
S= 3
B=2
O= 7 + 1= 8
We balance the equation by making the number of each element the same on both sides.
Starting with the Hydrogen:
LHS
H= 6 (from
RHS
H= 12 (from
Then the Sulphur:
LHS
S= 3 (from adding the 3 in front of the
RHS
S= 3
Then the Boron:
Add a 2 in front of
LHS: B= 2 and RHS: B=2
Finally, the Oxygen:
All we have to do here is make sure everything is adding up to the same number on both sides.
LHS
O= 7 (from
RHS
O= 7 (from
THE END whew!