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Answer 1 · 2017-05-04T19:01:58

5.12 M

This is simple plug and chug.

If you know your formula for #"molarity"#,

#color(white)(Aaaaaaaaaa)color(blue)("Molarity" = "moles of solute"/"Liter of solution")#

then you can simply plug where needed to find the molar concentration or molarity

First convert #"mL"->"L"#

#(975cancel"mL")/1 * (1*10^-3" L")/(1 cancel "mL") = 0.975" L"#

#"Molarity" = ("moles of solute")/("Liter of solution")->("5.0 moles of solute")/( 0.975" L of solution")->color(magenta)"5.12 M"#

#"Answer": 5.12" M", "where M is molar"#