The equation of line CD is y = −2x − 2. How do you write an equation of a line parallel to line CD in slope-intercept form that contains point (4, 5)?

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Answer 1 · 2017-05-02T17:16:21

#y = -2x+13#
See explanation this is a long answer question.

CD:# " "y=-2x-2#

Parallel means the new line (we will call it AB) will have the same slope as CD. #" "m =-2#

#:. y=-2x+b#

Now plug in the given point. #(x,y)#

#5=-2(4)+b#

Solve for b.

#5=-8+b#

#13=b#

So the equation for AB is

#y=-2x+13#

Now check

#y=-2(4)+13#
#y=5#

Therefore #(4,5)# is on the line #y = -2x+13#