How do you solve $8(2f - 2) = 7(3f + 2)$ ?

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Answer 1 · 2017-04-20T01:37:01

The final answer is $-6=f$ .

$8(2f-2)=7(3f+2)$

$(8*2f)+(8*-2)=(7*3f)+(7*2)->$ Expand both sides by using the Distributive Property.

$16f-16=21f+14$

$cancelcolor(red)(16f)-16cancelcolor(red)(-16f)=cancel(21fcolor(red)(-16f))5f+14->$ Subtract $16f$ from both sides.

$cancel(-16color(blue)(-14))-30=5fcancelcolor(blue)(+14)cancelcolor(blue)(-14)->$ Subtract $14$ from both sides.

$cancel(-30color(green)(/5))-6=cancelcolor(green)(5)fcancelcolor(green)(/5)->$ Divide both sides by 5.

$-6=f->$ Final answer!

How do you solve 8(2f - 2) = 7(3f + 2) 8(2f - 2) = 7(3f + 2) ?