How do you differentiate $f(x)=(2x+3)/6$ using the quotient rule?

Question

1653 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-20T00:01:13

here

using the formula $f(x)= (h(x))/g(x)$

$f'(x)=[g(x)*h'(x) - h(x)* g'(x)]/(g(x))^2$

$f'(x)=((6)*(2)-(2x+3)*0)/36= 12/36=2/6=1/3$

How do you differentiate f(x)=(2x+3)/6f(x)=(2x+3)/6 using the quotient rule?