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Question #69c90

1 Answer

Apr 5, 2017

#log(a+b)-log(a)#

Explanation:

Use the logarithm rule #log(a/b)=loga-logb#

Using this #log# rule, you are able to expand the compacted logarithm

#log((a+b)/a)=log(a+b)-log(a)#

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