How do you find the maximum and minimum of y=-2(x+1)^2+6?

1 Answer
David Britz
Mar 17, 2017

Find the vertex.

Explanation:

Finding the maximum or minimum for a quadratic equation like this one is code for finding the vertex.

If y=a(x-h)^2+k then vertex is (h,k)

In this case is -h=1 and k=6
So vertex is (-1,6)

Also, whenever a is negative in this format of equation that means you have a downward-opening parabola. Therefore the vertex is a maximum. So the maximum occurs at (-1,6). There is no minimum because the parabola continues down forever.

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