What is the the vertex of $y = x^2-4x+3$ ?

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Answer 1 · 2017-02-26T09:19:35

$(2, –1)$

The vertex formula is $(-b)/(2a)$

In this equation, $a = 1$ , $b = –4$ , and $c = 3$ .

Plugging the numbers into the equation, you should get

$(4)/(2(1)) = (4)/(2) = 2$

2 is the $x$ value of the equation. If you plug it into the equation, you'll end up with the $y$ value.

$y = (2)^2 – 4(2) + 3$
$y = –1$

So the vertex is $(2, –1)$

What is the the vertex of y = x^2-4x+3y = x^2-4x+3?